Question

What acceleration will result when a 12N net force applied to a 3 kg object?

Answer 1

• Mass=3kg
• Force=12N

`\\ \sf\longmapsto F=ma`

`\\ \sf\longmapsto a=(F)/(m)`

`\\ \sf\longmapsto a=(12)/(3)`

`\\ \sf\longmapsto a=4m/s^2`

Answer 2

`4 {ms}^( - 2)`

Step-by-step explanation:

The formula to find the acceleration is,

F = ma

F = force

m = mass

a = accelaration

Let's Solve

F = ma

a = F/a

a = 12N/3kg

= 4 ms^- 2

hope this helps you

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