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17 In Figure 5.18, the force L is 200 N and the large

piston on the right rises 1.0 cm.
a Calculate the force F.
b
Calculate the volume of oil that enters the
cylinder on the right. Remember the volume of a
cylinder is length x cross-sectional area.
c Use your answer to b to calculate the distance
that the piston on the left falls.
d Explain why the effort force in Figure 5.18 is less
than the force F

17 In Figure 5.18, the force L is 200 N and the large piston on the right rises 1.0 cm-example-1
User Sai Dandem
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1 Answer

3 votes

Answer:

A) 40N
B) 100cm^3
C) 5 cm

D) The ratio in the size of hydraulic presses creates a mechanical advantage of 5. Every 1 Newton of force inputed into the press becomes 5 Newtons of force on the other side. This, in turn, is off set by the distance the smaller piston must travel to raise the larger piston up, being 5cm converted into 1cm, 5x the distance. Further description in the explanation.

Explanation:

Output = Input • (Load/Effort)

200N = F • (100/20)

Load/Effort = Mechanical Advantage = 5

200N = F • 5

200N/5 = F

40N = F

If the piston rises 1.0cm and the cross section of the piston is 100cm^2, the oil entering the right tube is equal to 100cm^3 of substance.

If the oil leaving the left cylinder going into the right cylinder is 100cm^3 of liquid, then using the piston of size of 20cm^2, we can determine the piston travels 5 cm, as 100cm^3/20cm^2 = 5cm.

This can again be solved with Mechanical Advantage, as using the value previously determined, 5, we can simply multiply 1cm by 5.

This is another connection to how Mechanical Advantage is derived from the work being exerted. Work equals force x distance. If the output work is 100joules (100N x 1cm), then the input work must be equal, (40N x 5cm)

User Holman
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7.1k points