Question

Please resolve this problem for me! I've been having trouble with this for a while.

Answer 1

a) 41

b) -31

c) 25/3

Explanation:

The instructions explain what a function is pretty clearly.

Basically, whatever is in the parentheses next to the
`f`, you plug in to the expression that is the function.

ex:
`f(x) = x + 4`

`f(5) = 5 + 4 = 9`

Okay, onto the problems:

a)
`f(x) = 3x - 1`

First, plug in 14, since that is given:

`f(14) = 3(14) - 1`

and solve.

`f(14) = 42 - 1`

`f(14) = 41`

So, 41 is the answer to a.

b) Do the same thing you did in problem a. Plug in the number inside the parentheses and solve.

`f(-10) = 3(-10) - 1`

`f(-10) = -30 - 1`

`f(-10) = -31`

-31 is the answer to b.

c) For this problem, you have to do a bit of algebra.

First, take the base function f(x):

`f(x) = 3x - 1`

Then, set f(x) = 24:

`24 = 3x - 1`

and solve by isolating x.

`25 = 3x`

`(25)/(3) = x`

`x = (25)/(3)`

25/3 is the answer to c.