How many moles of solute particles are present in 1 mL of aqueous 0.060 M (NH4)2CO3?

asked Jan 5, 2023 22.0k views

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Molarity = moles of solute/volume of solution (litres)

n = Molarity x Volume

n = 0.033 mol/L x 10^-3 L

n = 3.3 x 10^-5 moles

Yazanpro answered Jan 11, 2023

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