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30 votes
30 votes
Solve the following compound inequality: −2(x + 4) + 10 < x − 7 OR −2x + 9 > 3(x + 8)

A: x < 3 or x > −3
B: x > 3 or x < −3
C: x < 7 or x > −3
D: x > 7 or x < −3

User Mecalito
by
2.7k points

1 Answer

14 votes
14 votes

#1


\\ \sf{:}\!\implies -2(x+4)+10<x-7


\\ \sf{:}\!\implies -2x-8+10<x-7


\\ \sf{:}\!\implies x+2x>2+7


\\ \sf{:}\!\implies 3x>9


\\ \sf{:}\!\implies x>(9)/(3)


\\ \sf{:}\!\implies x>3

#2


\\ \sf{:}\!\implies -2x+9>3(x+8)


\\ \sf{:}\!\implies -2x+9>3x+24


\\ \sf{:}\!\implies -2x-3x>24-9


\\ \sf{:}\!\implies -5x>15


\\ \sf{:}\!\implies x>(15)/(-5)


\\ \sf{:}\!\implies x>-3

User Houssem ZITOUN
by
3.1k points
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