Question

2. Perpendicular to y=1/2x -6 that passes through (6,-4)
PLEASE HELP ME ASAP

Answer 1

To get the slope (which we'll call n) of a line perpendicular to another line with slope (a/b), use

`n = (-b)/(a)`

Then we just plug in the point we want to cross and solve for the constant.

Explanation:

we see that m =
`(1)/(2)`

so,
`n = -(2)/(1) = -2`

now we have the equation

`-2x + b = y`

plugging in (6, -4) we get

`-2(6) + b = -4\\-12+b = 4\\b=4+12=16`

This gives us our function

`y = -2x + 16`