224k views
2 votes
Cannot solve this....

Cannot solve this....-example-1
User SaadK
by
3.4k points

1 Answer

3 votes

Answer:

Multiplying gives
\frac{7\sqrt[3]{x}}{\sqrt[3]{x^2}}, which still has an irrational number for a denominator

User Ivan Stoyanov
by
3.5k points