0 Comments
Answer:
Multiplying gives , which still has an irrational number for a denominator
9.4m questions
12.2m answers
![\frac{7\sqrt[3]{x}}{\sqrt[3]{x^2}}](https://img.qammunity.org/2023/formulas/mathematics/college/qab7n3oi20wypd66ip4djzevyjc7czipiz.png)
, which still has an irrational number for a denominator