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2 votes
Area of a trapezoid: A = =h(b₁
+ b₂);
Solve for b₂.

1 Answer

4 votes

Answer:
b_2 = (2A-hb_1)/(2)

Work Shown:


A = (1)/(2)h(b_1+b_2)\\\\2A = h(b_1+b_2)\\\\2A = hb_1+hb_2\\\\hb_1+hb_2 = 2A\\\\hb_2 = 2A-hb_1\\\\b_2 = (2A-hb_1)/(2)\\\\

User Manuel Mauky
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