Question

A line passing through the points (-1, -2) and (5, t) has a slope equal to -3.

Find the value of t.

Answer 1

Answer: t=-20

Explanation:

(-1,-2) (5,t) k=-3 t=?

y=kx+b

`\displaystyle\\\boxed {k=(y_2-y_1)/(x_2-x_1) }\\\\-3=(t-(-2))/(5-(-1)) \\\\-3=(t+2)/(5+1) \\\\-3=(t+2)/(6)`

Multiply both parts of the equation by 6:

`\displaystyle\\-3(6)=(t+2)/(6) (6)\\\\-18=t+2\\\\-18-2=t+2-2\\\\-20=t`