Question

Pls help!! need it fast.... I'm stuck


`2 log_(10)(5) + 3 log_(10)(2) - log_(10)(2)`
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Answer 1

So this is also going to stay the same, multiply first, divide, then you have your answer. Make sure if needed you need to round up your numbers.

Explanation:

Answer 2

2

Explanation:

Use power rule first:

\[tex]\log_{10}(5^2)+\log_{10}(2^3)-\log_{10}(2)[tex]

Now use product and quotient rule (if + in front inside goes on top and if - in front inside goes on bottom)

[\tex]\log_{10}(\frac{5^22^3}{2})[tex]

Reducing inside fraction;

[\tex]\log_{10}(5^22^2)[tex]

Simplifying inside:

[\tex]\log_{10}(100)[tex]

100 is a power of 10...that is 10^2=100 so final answer is 2.

[tex]\log_{10}(100)=2[\tex]