Answer: Choice 1):
{" The Large 16-inch diameter pizza for $12.99 "} ;
is clearly the better deal".
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Explanation:
For this problem; we can do an estimation—using "3" in lieu of "π" .
Note: the Area, "A" of a circle (we can call the pizza a "circle").
" A = π * r² " ; " A =
r² " ;
Let us "calculate" the "areas" for each pizza:
1) The large, 16-in diameter for $13 (we can round up to $13 for our purposes; as an estimate)—
Note: The radius; "r" ; "r = d/2 " ; (16 in) / 2 = 8 in.
" r = 8 in " ;
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So: " A ≅ 3 * (8 in²) ≅ 54 in².
$13 per 54 in² = $ (13 ÷ 54) = $ 0.24074074074 per in²
2) The $26 X-large with a radius, "r" = 16 in.
" A ≅ 3 * (16 in²) ≅ 48 in² .
$26 per 48 in² = $ (26/48) = $0.48148148148 per in²
Choice: #1): $ 0.24074074074 per in² ; is the better deal;
→ since: { $ 0.24074074074 per in² } ; costs significantly less than;
Choice: #2): { $0.48148148148 per in²}
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The answer is: Choice: 1)
" The Large 16-inch diameter pizza for $12.99 —is clearly the better deal."
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Hope this is helpful! Wishing you the best!
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