Answer:
-60 m/s²
Explanation:
We are not given the velocity of the plane at landing but we are given velocities at two time periods
V₅, the velocity of the plane 5 seconds after landing is 110 m/s
Plugging this into the velocity equation we get
(1)
Similarly
(2)
Subtract (1) from
![v_(15) - v_5 = (15a + v_0) - (5a + v_0) = (15a-5a) + (v_0-v_0) = 10a](https://img.qammunity.org/2023/formulas/mathematics/college/hux1bc8j9u52z2dkor3w2em61ghvs7pna8.png)
Therefore
![a = (v_(15) - v_5)/(10)](https://img.qammunity.org/2023/formulas/mathematics/college/qzdcnamkrf99kmdfahgz9nfc4mlgy2kcb4.png)
Given
![v_(15)= 50 m/s \textrm{ and } v_5 = 110m/s](https://img.qammunity.org/2023/formulas/mathematics/college/19czrwpjt68rva8bezhhw69ldfb6skhhen.png)
this evaluates to
-60 m/s²
The negative value is because the plane is actually decelerating which is a negative number