Question

Solve the system..???​

Answer 1

x=1

y=2

z=-3

Explanation:

-3x+2y+z=-2 ...(1)

x+4y-3z=18 ...(2)

2x-y-3z=9 ...(3)

multiply (1) by 3

-9x+6y+3z=-6 ...(4)

(2)+(4) gives

-8x+10y=12

divide by 2

-4x+5y=6 ...(5)

add (3) and (4)

-7x+5y=3 ...(6)

(5)-(6) gives

3x=3

divide by 3

x=1

from (5)

-4(1)+5y=6

5y=6+4=10

y=10/5=2

put in (1)

-3(1)+2(2)+z=-2

z=-2+3-4=-3

Answer 2

x = 1

y = 2

z = - 3

Explanation:

z=-2+3x - 2y Rearrange: x + 4y3z = 18 2xy-3z9 Substitute into one of the equations:

[x+4y-3(-2+ 3x – 2y) = 18

2x-y-3(-2+3x-2y) = 9

Apply Multiplicative Distribution Law: x + 4y + 6-9x+6y=18

[2x-y+6-9x+6y=9 Rearrange unknown terms to the left side of the equation: x + 4y - 9x+6y= 18-6 2xy +6 9x+6y=9

Calculate the sum or difference:

x + 4y - 9x+6y= 12

2xy + 6-9x+6y=9

Combine like terms: -8x+10y = 12 -7x+5y+6=9 Reduce the greatest common factor on both sides of the equation: - 4x + 5y = 6 -7x + 5y + 6 = 9 Rearrange unknown terms to the left side of the equation: -4x + 5y = 6 -7x + 5y = 9-6

Subtract the two equations: -4x+5y-(-7x

+5y)= 6-(9-6)

Remove parentheses: - 4x + 5y + 7x - 5y = 6

−9+6

Cancel one variable: - 4x + 7x = 6 - 9 + 6 Combine like terms: 3x = 6 - 9 + 6

Calculate the sum or difference: 3x = 3 Divide both sides of the equation by the coef

ficient of variable: x = 3/3 Calculate the product or quotient: x = 1 Substitute into one of the equations: -4+5y = 6

Rearrange unknown terms to the left side of the equation: 5y = 6 + 4 Calculate the sum or difference: 5y = 10 Divide both sides of the equation by the coef ficient of variable: y = 10/5 Calculate the product or quotient: y = 2

The solution of the system is:

x = 1

y = 2

Substitute into one of the equations:

z = - 2 +3-2x2

Calculate the product or quotient:

z = - 2 + 3 - 4

Calculate the sum or difference:

z = 1 - 4

Calculate the sum or difference:

z = - 3 x = 1 y = 2 -3

The solution of the system is:

x = 1

y = 2

z = - 3