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How many hydrogen atoms are present in 4 mg of aspartame?

User Dave Olson
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molecular \: formula \: = C_(14)H_(18)N_(2)O_(5) \\


molar \: mass = 294\: g.mol {}^( - 1)


n_(aspartame) = (mass)/(molar \: mass) = \frac{4 * 10 {}^( - 3) }{294} = 1.36055 * 10 {}^( - 5) moles \\


1 \: mole \: asp = 18 \: moles \: hydrogen \\ n_(hydrogen) = 18 * n_(aspartame)


atoms_(hydrogen) = n_(hydrogen) * 6.022 * 10 {}^(23) \\ atoms_(hydrogen) = 0.0002448979591 * 6.022 * 10 {}^(23) \\ atoms_(hydrogen) = 1.4747755 * 10 {}^(20) atoms

User Richard Hurt
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