Logx + Logx(x+3)=2log(x+1)

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Explanation:

Logx + Log(x+3)=2log(x+1)

Log x(x+3) = Log (x+1)²

x(x+3)=(x+1)²

x²+3x = x²+2x+1

delete x², we find

3x = 2x+1

3x-2x = 1

x = 1

Ivanatpr answered Aug 8, 2022

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