HELP ME AGAIN!!!!! I NEED 100% (ALGEBRA)

Gerasimos asked Aug 4, 2023

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Gerasimos asked Aug 4, 2023

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23 votes

Answer:

(foh)(x)=-x^2 +6x+31

Explanation:

$\huge f(x)=13-x\ \ \ \ \ \ h(x)=x^2-6x-18 \\ \\(foh)(x)=f[h(x)]=13-(x^2-6x-18)=-x^2 +6x+31$

Dugong answered Aug 10, 2023

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