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Differentiate 4x^2sinx-3x^2cosx

User Roledenez
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1 Answer

5 votes

Answer:

(3x² + 8x)sin x + (4x² - 6x)cos x

Explanation:

d/dx (4x^2sin x - 3x^2cos x) =

= 4x² × d/dx sin x + sin x × d/dx 4x² - (3x² × d/dx cos x + cos x × d/dx 3x²)

= 4x² × cos x + sin x × 8x + 3x² × sin x - cos x × 6x

= 4x² cos x + 8x sin x + 3x² sin x - 6x cos x

= (3x² + 8x)sin x + (4x² - 6x)cos x

User Diego Carrera
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