Question

Find the distance and midpoint of AB if A = (10, -6) and B = (0, -2).

Distance of AB
Midpoint of AB :(
(Round to the nearest tenth.)
)

Answer 1

distance = 10.8 units

midpoint: (5, -4)

Explanation:

To find distance

`\sf d = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`

`\sf d = √((-2 -(-6))^2 + (0 -10)^2)`

`\sf d = √((4)^2 + (-10)^2)`

`\sf d = √(16+ 100)`

`\sf d = √(116)\quad \approx \quad 10.8`

To find midpoint

`\sf (x_m, y_m) = \left((x_1+x_2)/(2), (y_1+y_2)/(2)\right)`

`\sf (x_m, y_m) = \left((10+0)/(2), (-6-2)/(2)\right) = (5, -4)`