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I’m the following right triangle PQR,find the missing side x, and R if angle Q=70 degrees.Also find the 6 T ratios

Need help! I’m the following right triangle PQR,find the missing side x, and R if-example-1
User Promzy
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1 Answer

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Explanation:

first of all, there is the rule for all types of triangles : the sum of all angles in a triangle is always 180°.

and for right-angled triangles there is also Pythagoras :

c² = a² + b²

with c being the Hypotenuse (the side opposite of the 90° angle), and a, b being the legs.

so, with these rules we can get all missing elements :

180 = 90 + angle Q + angle R

180 = 90 + 70 + angle R

20° = angle R

30² = 24² + x²

900 = 576 + x²

324 = x²

x = sqrt(324) = 18

the 6 trigonometric ratios (functions) of any angle are

sine

cosine

tangent

cotangent

secant

cosecant

there is something very wrong with the numbers.

a triangle with the sides 30, 24, 18 cannot have the angles 90°, 70°, 20°.

the angles are with these sides

P = 90°

Q = 36.87°

R = 53.13°

or a triangle with the angles 90°, 70°, 20° and the Hypotenuse = 30 has the legs

PQ = 10.261

PR = 28.191

the given sides do not fit to the given angles.

I will give you now the trigonometric ratios of Q based on the calculated side lengths 30, 24, 18 and ignore the specified angle sizes :

sin(Q) = opposite/ Hypotenuse = 18/30 = 3/5 = 0.6

Q = 36.87°

cos(Q) = adjacent/ Hypotenuse = 24/30 = 4/5 = 0.8

Q = 36.87°

tan(Q) = opposite/ adjacent = sin(Q)/cos(Q) = 18/24 =

= 3/4 = 0.75 Q = 36.87°

cot(Q) = adjacent/ opposite = 24/18 = 4/3 = 1.33333...

Q = 36.87°

sec(Q) = Hypotenuse/ adjacent = 30/24 = 5/4 = 1.25

Q = 36.87°

csc(Q) = Hypotenuse/ opposite = 30/18 = 5/3 = 1.6666...

Q = 36.87°

if the sides of the right-angled triangle are truly 30, 24, 18, then Q = 36.87° (confirmed by all 6 trigonometric ratios), and above are all 6 trigonometric ratios for that angle.

User Ostad
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