Question

8. A monorail train traveling at 80 km/h must be stopped at 40 m. a) What average acceleration

is required and b) what is the stopping time?

Answer 1

Step-by-step explanation:

initial velocity= 80km/hr = 22.22 m/s

distance= 40m

Final velocity= 0m/s ( as it needs to be stopped)

Using third equation of motion,

=> 2as = v² - u²

=> 2a * 40m = 0² - (22.22 m/s)²

=> a = - 493.72/80 m/s²

=> a = - 6.17m/s²

Using first equation of motion,

=> a = v - u /t

=> -6.17 = 0-22.22/t

=> t = -22.22/-6.17 s

=> t ≈ 3.7 s = stopping time