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The coordinates of the vertices of triangle ABC are A(4,-3), B(2,5), and C(-4,2)? Find the perimeter of triangle ABC to the nearest tenth

User Sunilkjt
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1 Answer

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Answer: 24.4

Explanation:


AB=√((4-2)^2 +(-3-5)^2)=√(4+64)=√(68)\\\\BC=√((2-(-4))^2 +(5-2)^2)=√(6^2 +3^2) =√(45)\\\\AC=√((4-(-4))^2 +(-3-2)^2)=√(64+25)=√(89)\\\\\therefore \text{Perimeter }=√(68)+√(45)+√(89) \approx 24.4

The coordinates of the vertices of triangle ABC are A(4,-3), B(2,5), and C(-4,2)? Find-example-1
User Rishi Dwivedi
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4.5k points