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After distributing the terms (3x - 7) (2x + 5), you get a new expression of the form ax²+bx+c. What is the value of a? What is the value of b? What is the value of c?
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After distributing the terms (3x - 7) (2x + 5), you get a new expression of the form

ax²+bx+c.
What is the value of a?
What is the value of b?
What is the value of c?

User Dipesh Gupta
by
7.8k points

1 Answer

3 votes
first multiply (3x-7) and (2x+5)
i already did the multiplication so i am writing the answer
(3x-7)(2x+5)
6x^2+x-35

a is 6
b is 1
c is -35

if you want me to share how i did the multiplication then do let me know
User Steven Grosmark
by
6.3k points
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