So, amount of static friction acting on the truck if the truck does not move is 2,000 N.
Introduction
Hi ! Here I will help you to solve the problem about static friction. Friction is a force that inhibits or reduces the value of the force acting on an object. If viewed from the direction of the initial force, the frictional force will always have a negative value (-) due to always have opposite direction from the intial direction. Friction is divided into two types, namely :
- Static friction (
), occurs when the resultant force is 0 N or in other words the object is still at rest. - Kinetic friction (
), occurs when the object has moved, so that the resultant force not 0 N.
Formula Used
The formula used in this case is the equation for static friction. Pay attention at below.
![\sf{\sum F = 0}](https://img.qammunity.org/2023/formulas/physics/high-school/dnmso4igh52j07z3tc9qvh5gvqro0twexq.png)
![\sf{F - f_s = 0}](https://img.qammunity.org/2023/formulas/physics/high-school/i57xsiwu866l8zx0309ktpjjfu446d9plu.png)
![\boxed{\sf{\bold{F = f_s}}}](https://img.qammunity.org/2023/formulas/physics/high-school/pkycrqjwlrzjw7tno2enwbjfn9qs8fd81f.png)
With the following condition :
= resultant of the force (N)- F = force that applied to object (N)
= static friction (N)
Solution
We know that :
- The truck affected by static friction
- F = force that applied to object = 2,000 N
What was asked ?
= static friction = ... N
Step by step :
![\sf{\sum F = 0}](https://img.qammunity.org/2023/formulas/physics/high-school/dnmso4igh52j07z3tc9qvh5gvqro0twexq.png)
![\sf{F - f_s = 0}](https://img.qammunity.org/2023/formulas/physics/high-school/i57xsiwu866l8zx0309ktpjjfu446d9plu.png)
![\sf{F = f_s}](https://img.qammunity.org/2023/formulas/physics/high-school/68xzc933c2yr8rpyhwag9y6fa4u4rb8r5u.png)
![\boxed{\sf{2,000 \: N= f_s}}](https://img.qammunity.org/2023/formulas/physics/high-school/xs1exg5w390j4qwpfgieq2pt1ps7m2bk83.png)
Conclusion
So, amount of static friction acting on the truck if the truck does not move is 2,000 N.