Question

Can someone help me please

Answer 1

`\displaystyle\\Answer:\ y=(x)/(3)-60`

Explanation:

y=kx+b (1)

The formula for the slope coefficient of the straight line

`\displaystyle\\\boxed {k=(rise)/(run)=(y_2-y_1)/(x_2-x_1) }`

Choose two coordinate points belonging to the line: (0,-60) (30,-50)

Hence,

`\displaystyle\\k=(-50-(-60))/(30-0) \\\\k=(-50+60)/(30)\\\\k=(10)/(30) \\\\k=(1*10)/(3*10) \\\\k=(1)/(3) \\\\Thus, \ y=(1)/(3) x+b\\(0,-60)\\-60=(1)/(3) (0)+b\\-60=0+b\\-60=b\\\\As \ a\ result:\\\\y=(x)/(3)-60`

Answer 2

y=1/3(x+(3*(-60))) => y=1/3(x-180)