Question

Please need help from math experts!!!! Struggling so hard…

Answer 1

Explanation:

A(10,10) B(b,10b)

ax-2y=30

`a)\\a(10)-2(10)=30\\10a-20=30\\10a-20+20=30+20\\10a=50`

Divide both parts of the equation by 10:

a=5

Hence,

5x-2y=30

5(b)-2(10b)=30

5b-20b=30

-15b=30

Divide both parts of the equation by -15:

b=-2

Thus,

a=5 b=-2

`b)\\A(10,10)\ \ \ \ \ \ B(-2,-20)\\ \displaystyle\\C(x_C,y_C)=((10+(-2))/(2) ,(10+(-20))/(2) )\\\\C(x_C,y_C)=((10-2)/(2),(10-20)/(2) )\\\\C(x_C,y_C)=((8)/(2) ,(-10)/(2))\\\\C(x_C,y_C)=(4,-5)\\Hence,\ C(4,-5)`

`5x-2y=30\\5x-2y+2y=30+2y\\5x=30+2y\\5x-30=30-30+2y\\5x-30=2y\\`

Divide both parts of the equation by 2:

2.5x-15=y

`c)\\y=2.5x-15`

The equation of the perpendiqular bisector

`\boxed {y=-(x)/(k) +b}`

Hence,

`\displaystyle\\y=-(x)/(2.5)-15 \\\\y=-0.4x-15`