Question

find the equation of the straight line through the point (2,3) whose intercept on x-axis is twice that on y-axis​

Answer 1

y = -1/2x + 4

Explanation:

y=mx+b

3 = m* 2 + b .. pass (2,3)

y = 0 x = - b/m .. x intercept

-b/m = 2b .... divide b both side

-1/m = 2 m= -1/2

b = 3 - 2m = 3 - (2*-1/2) = 4

equation: y = -1/2x + 4