Question

Anyone can help me to solve this?​

Answer 1

1. 2x²-x-6=0

2. x²-7x+10=0

3. a²+13a+12=0

4. 2x²-x-6=0

5. 2x²-x-6=0

Explanation:

Expand the factors by multiplying each terms in the bracket to the others in the other bracket.

Then collect like terms and simplify.

Something like :

(x+2)(2x-3)=0

x*2x*x*-3*2*2x*2*-3=0

2x²-3x+4x-6=0

2x²-x-6=0

Answer 2

1.)
`\sf 2x^2 +x - 6=0`

2.)
`\sf x^2-7x+10=0`

3.) 
`\sf a^2 + 13a + 12 = 0`

4.)
`\sf 2x^2 +x - 6=0`

5.)
`\sf 2x^2 +x - 6=0`

Explanation

`\sf Formula: (a+b)(c+d) = ac + ad + bc + bd`

2.)

`\sf (x-2)(x-5)=0`

`\sf x^2-5x-2x+10=0`

`\sf x^2-7x+10=0`

3.)

`\sf (a+12)(a+1)=0`

`\sf a^2 + a + 12a + 12 = 0`

`\sf a^2 + 13a + 12 = 0`

4.)

`\sf (x + 2)(2x-3)=0`

`\sf 2x^2 -3x + 4x - 6=0`

`\sf 2x^2 +x - 6=0`

5.)

`\sf (x+2)(2x-3)=0`

`\sf 2x^2 -3x + 4x - 6=0`

`\sf 2x^2 +x - 6=0`

Question 1, 4, 5 are same and repeated questions. Solution's same.