Question

Solve the quadratic equation 3x²-3x-1=0?
(by using the square method)​

Answer 1

x=1 and x=-1/3

Explanation:

`3x^2-2x-1=0\\\\3(x^2-(2)/(3)x-(1)/(3))=0\\ \\3(x^2-(2)/(3)x-(1)/(3)+(4)/(9))=3((4)/(9))\\ \\ 3(x^2-(2)/(3)x+(1)/(9))=(4)/(3)\\ \\ 3(x-(1)/(3))^2=(4)/(3)\\ \\(x-(1)/(3))^2=(4)/(9)\\ \\x-(1)/(3)=\pm(2)/(3)`

`x-(1)/(3)=(2)/(3)\\ \\x=(3)/(3)\\ \\x=1`

`x-(1)/(3)=-(2)/(3)\\ \\x=-(1)/(3)`

Therefore, x=1 and x=-1/3