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A function h(t) is known to be exponential; that is h(t)=ab^t. if h(3)=6 and h(5)=24 find b and a

User Dertseha
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3 votes

We have:


6 = ab^3


24 = ab^5

If you divide the second equation by the first:


(24)/(6) = (ab^5)/(ab^3)


4 = b^2

b = 2 (we discard the negative solution because in the exponential function the base must be positive.)

Then:


6 = a\cdot 2^3


6 = a\cdot 8


a = (6)/(8)


a = (3)/(4) = 0.75

User Primulaveris
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