Question

Ava is the oldest of four siblings whose ages are consecutive odd integers. If the sum of their ages is

104

Answer 1

The age of Ava be,

→ x (age)

Let's form the equation,

→ (x) + (x - 2) + (x - 4) + (x - 6) = 104

→ 4x - 12 = 104

Then the age of Ava will be,

→ 4x - 12 = 104

→ 4x = 104 + 12

→ x = 116/4

→ [ x = 29 ]

Hence, the age of Ava is 29. Then the ages of other siblings will be,

→ x - 2 = 29 - 2 = 27

→ x - 4 = 29 - 4 = 25

→ x - 6 = 29 - 6 = 23

Therefore, the age of the siblings from oldest to youngest is 29, 27, 25 and 23 respectively.

Answer 2

• Ava is 29

Explanation:

It is assumed you are looking for Ava's age.

Let Ava's age be x, then the ages of the other's are:

• x - 2, x - 4 and x - 6

Sum of the four ages is 104.

Show this as equation and solve for x:

• x + x - 2 + x - 4 + x - 6 = 104
• 4x - 12 = 104
• 4x = 104 + 12
• 4x = 116
• x = 116/4
• x = 29

Ava is 29 years old.