Question

Find the range of this
quadratic function.
Y=x2+2x

Answer 1

Answer: -1≤y≤+∞

Explanation:

`y=x^2+2x\\y=x^2+2x+1-1\\y=(x^2+2x+1)-1\\y=(x+1)^2-1\\(x+1)^2\geq 0\\Hence,\\y\geq -1\\Or\\-1\leq y\leq +\infty`

Answer 2

[-1,infinity) would be the range