Answer:
20.38 m/s^2 deceleration
Step-by-step explanation:
295 km/hr = 91.94 m/s
v goes from 91.94 to 0 average v = 40.97 m/s
d = vt
205 = 40.97 t t = 5 seconds
d = vo t - 1/2 a t^2
205 = 91.94 ( 5) - 1/2 (a)(5^2)
a = 20.38 m/s^2 (DECELERATION)
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