Question

Determine the empirical formula of a compound that was found to contain 6.412 g potassium, 2.292 g n, and 7.871 g o.

Answer 1

Answer: KNO3

Explanation: Hello! the answer to your question is KNO3

We get this by dividing each by their molar mass

Potassium: 6.412/39.10 = 0.1639

Nitrogen: 2.292/14.01 =0.1635

Oxygen: 7.871/16.00 = 0.4919

We then pick the smallest of these results, this would be Nitrogen and divide everything with this answer, 0.1635

Potassium: = 0.1639/0.1635 = 1.002, about 1

Nitrogen: 0.1635=0.1635, 1

Oxygen: = 0.4919, 3.008, about 3

Now that we have the number of moles, we put it together, making KNO3