Question

Lesson 5 Practice Problems

1. What is the value of
when x = 5?
4(x-2)(x-3)+7(x-2)(x - 5)- 6(x-3)(x - 5)

Answer 1

Explanation:

The required value of equation at x = 5 is 24.

Given ;

Equation is = 4(x-2)(x-3) + 7(x-2)(x-5) - 6(x-3)

We have to calculate the value of expression when x = 5

To solve the equation substitute x = 5 in the given equation

= 4(x-2)(x-3) + 7(x-2)(x-5) - 6(x-3)(x-5)

= 4(5-2)(5-3) + 7(5-2)(5-5) - 6(5-3)(5-5)

Simplify the equation

= 4(3)(2) + 7(3)(0) - 6(2)(0)

= 4.(6) + 7(0) - 6(0)

= 24 + 0 - 0

= 24

The required value of the equation at x = 5 is 24.