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Graphing/Slopes (Easy points!!) (ASAP) (URGENT) (Please check my other questions)



Graphing/Slopes (Easy points!!) (ASAP) (URGENT) (Please check my other questions) ​-example-1
User Richardr
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7 votes

Answer:

The statement is incorrect because an inverse relationship between y and x would imply that the graph would be a downward curved graph whose slope changes rather than linear which has constant slope (see image).

Best to express this situation as:
There is a linear relationship between y and x with a negative constant slope. The keyword here is constant since the slope is the same in a linear relationship

Explanation:

An inverse relationship exists between y and x when y is proportional to the reciprocal of y

This would be expressed in the form
y
(1)/(x)

As x decreases , y increases or vice-versa. It is often expressed in equation form as
y=(k)/(x) or
y = kx^(-1) where k is a constant and whose graph is curved in nature. The slope is changing for the range of x values not constant as would be the case for a linear graph

All we can say about the data is that there is a linear relationship between y and x with a negative constant slope

Graphing/Slopes (Easy points!!) (ASAP) (URGENT) (Please check my other questions) ​-example-1
User Anthony Keane
by
8.5k points

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