Question

Х+2у=5

3x+6y=-10

Just wondering how to solve this with either substitution or elimination

Answer 1

x=5 y=0

Explanation:

`x = - 2y + 5 .......(3)\\ putt \: value \: in \: eq \: 2 \\ 3( - 2y + 5) + 6y = - 10 \\ - 6y + 15 + 6y = - 10 as \: te \: value \: after \\subtraction \:is \: 0 \\ y = 0 \\ put \: the \: value \: of \: y \:in \: eq3 \\ x = - 2(0) + 5 \\ x = 5`