Question

A weight lifter does 2940 J of work to lift a 150kg barbell over his head. If he does so in 5 seconds, how much power did he exert?

Answer 1

Power Is how much you need to work for every second, power formula is:

`\huge \boxed{ {\sf P = (W)/(t) }}`

With:

P = Power (watts)

W = Work (joule)

t = times (secon)

_________

Data Given:

Work = 2940 Joule

t = 5 Second

______

Power = ?

______

Answer:

= W/t

= 2940/5

= 2940 ÷ 5

= 588 Watts

The Power he exert is 588 watts

Answer 2

Step-by-step explanation:

W = 2940 J

m = 150 kg

t = 5 s

find P =?

P = W/t = 2940/5 = 588 watts