Question

Nikhil and Mae work at the same company. Nikhil has been at the company 4 times as long as Mae. Nikhil's time at the company is 8 more than 2 times Mae's time. The following system of equations models the scenario:

x = 4y
x = 8 + 2y

How many years has each person been employed by the company?
please help
Nikhil has been with the company for 16 years, while Mae has been there for 4 years.
Nikhil has been with the company for 24 years, while Mae has been there for 6 years.
Nikhil has been with the company for 20 years, while Mae has been there for 5 years.
Nikhil has been with the company for 16 years, while Mae has been there for 4 years.

Answer 1

Upon solving the system of linear equations, Nikhil has been with the company for 16 years and Mae for 4 years.

Step-by-step explanation:

The student asks for the solution to a system of linear equations representing the years of employment for Nikhil and Mae at a company. According to the system, x represents the years Nikhil has been at the company, and y represents Mae's years at the company. The system is:

• x = 4y
• x = 8 + 2y

The solution to the system can be found by setting the two expressions for x equal to each other:

4y = 8 + 2y.

Subtracting 2y from both sides gives:

2y = 8.

Dividing both sides by 2 gives:

y = 4.

Substituting y back into the first equation gives:

x = 4 * 4,

x = 16.

Therefore, Nikhil has been employed by the company for 16 years, and Mae has been there for 4 years.

Answer 2

Answer: Nikhil has been with the company for 16 years, while Mae has been there for 4 years.

Step-by-step explanation:

i got it right on my quiz :D