Question

I need help on how to do this problem.

Many thanks!

Answer 1

Step-by-step explanation:

First, we. need to convert the initial velocity of 85 km/hr into m/s:

`85\:\frac{\text{km}}{\text{hr}}×\frac{1000\:\text{m}}{1\:\text{km}}×\frac{1\:\text{hr}}{3600\:\text{s}}=23.6\:\text{m/s}`

Next, we're going to use the equation below:

`v^2 = v_0^2 + 2ax`

Since
`v=0\:\text{and}\:a = -1.3\:\text{m/s,}^2` we can solve for the distance x:

`x = -(v_0^2)/(2a) = -\frac{(23.6\:\text{m/s})^2}{2(-1.3\:\text{m/s}^2)}`

`\:\:\:\:\:\:\:=214.2\:\text{m}`