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The liquid air contains 200 g of liquid oxygen and 800 g of liquid nitrogen.

The specific heat capacity of liquid oxygen is 1.7J/(g °C) and the specific heat capacity of liquid nitrogen is 2.0J/(g °C).
Calculate the thermal energy needed to warm the liquid from -205°C to -196°C.
State the formula that you use in your calculation.

1 Answer

4 votes

Answer:

17460 J

Step-by-step explanation:

Q = m c Δ T is the formula to use

you have two masses and two different 'c' values to consider

Q = 200 g (1.7 J/(g-C)( 205-196 C) + 800 (2.0)(205-196)

Q = 17460 J

User DurandA
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