Question

Please help!! “The length of a rectangle is 2 yd longer than it’s width. If the perimeter of the rectangle is 56 yd, find it’s length and width.”

Answer 1

24

Explanation:

x=Width of rectangle

x+2= Length of the rectangle

2(x+2) + 2x = 24 (the perimeter)

2x+4 +2x = 24

4x + 4 = 24

Correct me if i am wrong please