Question

An airplane accelerates from a velocity of 25.88 m/s at a constant rate of 4.21 m/s^2 over 590.39 m. What is its final velocity?

Answer 1

75.1 m/s

Step-by-step explanation:

vf = vo + at

d = do + vo t + 1/2 a t^2 <====use this to find time...

then use this 'time' in the first equation to find vf

590.39 = 0 + 25.88 t + 1/2 (4.21) t^2 Use Quadratic Formula

to find t = 11.69 s

Now use the first equation:

vf = 25.88 + 4.21 (11.69) = 75.1 m/s