Question

Kellie has 6/7 as many paper clips as Junjie. Minghua has 3 times as many paper clips as Kellie. Given that Minghua has 2552 more paper clips than Junjie. (a) how many paper clips do the 3 children have in total? (b) how many paper clips does Minghua have?​

Answer 1

Answer: 6,192 paperclips, 3,826 paperclips

Explanation:

a) To find the sum of all the children's paperclips, you must find each of them.

First, to start off, create some equations that represent this information:

k = j *
`(6)/(7)`

m = 3k

m = j + 2552

Then, for starts you can use the equation m = 3k and plug in for the variables

m = 3k

(j+2552) = 3(j * 6/7)

j + 2552 = 3j + 2.57

2549.43 = 2j

j = 1274.715

j = 1274 (round down because you can't have a fraction of a paper clip)

Next, use j to solve the other equations

m = j + 2552

m = 1274 + 2552

m = 3826

k = j * 6/7

k = 1274 * 6/7

k = 1092

sum = k + j + m

sum = 1092 + 1274 + 3826

sum = 6,192 paperclips

b) We already know m, which is 3826.

3,826 paperclips