219k views
17 votes
Solve the equation for the variable:

1.) x^2 - 12x = 45

2.) x^2 - 6x = 7

User Terry Wei
by
7.8k points

2 Answers

7 votes

1. )


x^(2) -12x=45\\x^(2) -12x-45 = 0\\(x-15)(x+3) = 0\\x = -3, 15

2. )


x^(2)-6x=7\\x^(2) -6x-7=0\\(x-7)(x+1) = 0\\x = -1, 7

User Etienne Laurin
by
8.4k points
9 votes

Answer:

Given Below.

Step-by-step explanation:

(a)


x^2 - 12x = 45


x^2 - 12x -45 = 0


x^2 - 15x + 3x - 45 = 0


x ( x-15) + 3 ( x - 15) = 0


(x+3)(x-15) = 0


x = -3 , 15

(b)


x^2 - 6x = 7


x^2 - 6x -7 = 0


x^2-7x + x -7 = 0


x(x-7)+1(x-7) = 0


(x+1)(x-7) =0


x = -1, 7

User Therealrootuser
by
6.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories