Please help me with this pre calc question and show ur work!!

asked Nov 13, 2023 34.5k views

1 vote

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3 votes

Part (a)

$f(x)=x^2 +x-10 \\ \\ f(-2)=(-2)^2 +(-2)-10 \\ \\ f(-2)=-8$

Part (b)

f(4x)=(4x)^2 +(4x)-10=16x^2+4x-10

Part (c)

$f(x+3)=(x+3)^2 + (x+3)-10 \\ \\ =x^2 + 6x+9+x+3-10 \\ \\ =x^2 + 7x+2$

Reggie Carey answered Nov 19, 2023

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