Question

What are the roots of the polynomial equation 0=x^2-12x -64

Answer 1

x = - 4, x = 16

Explanation:

x² - 12x - 64 = 0

Consider the factors of the constant term (- 64) which sum to give the coefficient of the x- term (- 12)

The factors are + 4 and - 16 , since

4 × - 16 = - 64 and 4 - 16 = - 12 , then

(x + 4)(x - 16) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 16 = 0 ⇒ x = 16