1 Answer

James Beith · Answer 1 · 2023-12-27T04:19:36+0000

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

Let's equate the function with 0 to find its roots :

$\qquad \sf  \dashrightarrow \: \frac{ {x}^(2) - 9 }{2 + x} = 0$

$\qquad \sf  \dashrightarrow \: {x}^(2) - 9 = 0$

[ assuming x is not equal to -2, as it isn't defined on -2 ]

$\qquad \sf  \dashrightarrow \:(x + 3)(x - 3) = 0$

so, the required roots are : -3 and 3

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