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The x intercepts of the function f(x) = 2x(x-5)^2(x+4)^3
are​

User Jaxvy
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2 Answers

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x- intercepts (0,0) , (5,0) , (-4,0)

y- intercepts (0,0)

Hope this helped

User Gnasher
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Answer:


\boxed{\sf x- intercepts = 0 , 5 \ and \ -4}

Explanation:

A function is given to us and we need to find the x Intercepts of the graph of the given function . The function is ,


\sf \implies f(x) = 2x( x - 5 ) ^2(x+4)^3

For finding the x intercept , equate the given function with 0, we have ;


\sf \implies 2x ( x - 5 )^2(x+4)^3= 0

Equate each factor with 0 ,


\sf \implies 2x = 0

Divide both sides by 2 ,


\sf \implies\bf x = 0

Again ,


\sf \implies ( x - 5)^2=0

Taking squareroot on both sides,


\sf \implies x - 5 = 0

Add 5 to both sides,


\sf \implies \bf x = 5

Similarly ,


\sf \implies \bf x = -4

Hence the x Intercepts are -4 , 0 and 5 .

{ See attachment also for graph } .

The x intercepts of the function f(x) = 2x(x-5)^2(x+4)^3 are​-example-1
User Daniel Bejan
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