Answer:
x + 2y = 8 c=x+3y x≥2 y≥0 By considering the options (A) and (B) For option (A) x=8 and y=0 x+2y=8 put values of x and y in equation 8+2*0=8, which satisfies the equation now c = 8+3*0=8 Now, for option (B) x=2 and y=3 x+2y=8 put values of x and y 2+2*3=8, which satisfies the equation. now c = 2+3*3=11 As we have to find the minimum value of c.
Explanation: