Question

Prove: An even times an even is
an even.
2n 2m [? ]mn
= even
=

Answer 1

2n × 2m = 4mn

Assume n = 1, m = 1

Explanation:

`2n \cdot 2m=\:?\\= \left(2 \cdot n\right) \cdot \left(2 \cdot m\right)\\= 2 \cdot 2\\= 4\\= 4mn\\\mathrm{Even}`

Hope this helps!

Answer 2

Answer: 4nm

You'll need to take 2 * 2 separately which will equal 4

Then you need to n * m which is nm

Thus equaling

4nm